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The following table summarizes the expected outcome of alkyl halide reactions with nucleophiles. It is assumed that the alkyl halides have one or more beta-hydrogens, making elimination possible; and that low dielectric solvents (e.g. acetone, ethanol, tetrahydrofuran & ethyl acetate) are used. When a high dielectric solvent would significantly influence the reaction this is noted in red. Note that halogens bonded to sp2 or sp hybridized carbon atoms do not normally undergo substitution or elimination reactions with nucleophilic reagents.
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The two models displayed below start as methyl bromide, on the left, and ethyl bromide, on the right. These may be replaced by isopropyl, tert-butyl, neopentyl, and benzyl bromide models by pressing the appropriate buttons. (note that when first activated, this display may require clicking twice on the selected button.) In each picture the nucleophile is designated by a large violet sphere, located 3.75 Angstroms from the alpha-carbon atom (colored a dark gray), and located exactly opposite to the bromine (colored red-brown). This represents a point on the trajectory the nucleophile must follow if it is to bond to the back-side of the carbon atom, displacing bromide anion from the front face. With the exception of methyl and benzyl, the other alkyl groups present a steric hindrance to the back-side approach of the nucleophile, which increases with substitution alpha and beta to the bromine. The hydrogen (and carbon) atoms that hinder the nucleophile\'\s approach are colored a light red. The magnitude of this steric hindrance may be seen by moving the models about in the usual way, and is clearly greatest for tert-butyl and neopentyl, the two compounds that fail to give substitution reactions.
View Isopropyl Bromide View Neopentyl Bromide Return to Methyl Bromide | View tert-Butyl Bromide View Benzyl Bromide Return to Ethyl Bromide |
The following animation shows the reaction between methylthiolate and (S)-2-bromobutane:
Spacefill Model Ball&Stick Model Stop Motion (on/off) |
The following animation shows the ionization of 3-bromo-3-methylhexane, |
Spacefill Model Ball&Stick Model Stop Motion (on/off) |
The importance of maintaining a planar configuration of the trigonal double-bond carbon components must never be overlooked. For optimum pi-bonding to occur, the p-orbitals on these carbons must be parallel, and the resulting doubly-bonded planar configuration is more stable than a twisted alternative by over 60 kcal/mole. This structural constraint is responsible for the existence of alkene stereoisomers when substitutuion patterns permit. It also prohibits certain elimination reactions of bicyclic alkyl halides, that might be favorable in simpler cases. For example, the bicyclooctyl 3º-chloride shown below appears to be similar to tert-butyl chloride, but it does not undergo elimination, even when treated with a strong base (e.g. KOH or KOC4H9). There are six equivalent beta-hydrogens that might be attacked by base (two of these are colored blue as a reference), so an E2 reaction seems plausible. The problem with this elimination is that the resulting double bond would be constrained in a severely twisted (non-planar) configuration by the bridged structure of the carbon skeleton. The carbon atoms of this twisted double-bond are colored red and blue respectively, and a Newman projection looking down the twisted bond is drawn on the right. Because a pi-bond cannot be formed, the hypothetical alkene does not exist. Structural prohibitions such as this are often encountered in small bridged ring systems, and are referred to as Bredt\'\s Rule.
Bredt\'\s Rule should not be applied blindly to all bridged ring systems. If large rings are present their conformational flexibility may permit good overlap of the p-orbitals of a double bond at a bridgehead. This is similar to recognizing that trans-cycloalkenes cannot be prepared if the ring is small (3 to 7-membered), but can be isolated for larger ring systems. The anti-tumor agent taxol has such a bridgehead double bond (colored red), as shown in the following illustration. The bicyclo[3.3.1]octane ring system is the smallest in which bridgehead double bonds have been observed. The drawing to the right of taxol shows this system. The bridgehead double bond (red) has a cis-orientation in the six-membered ring (colored blue), but a trans-orientation in the larger eight-membered ring.
'); generator.document.write('The following animation illustrates the methoxide base-induced elimination of 2-bromobutane. Note the anti-configuration of the reacting groups (H & Br). The product in this case would be trans-2-butene. A similar set of conformations would generate the cis-isomer, but the energy of the cis-transition state is slightly higher due to gauche-like crowding of the methyl groups.
This animation will repeat six times and then stop.
The following animations show the elimination of 2-bromobutane, CH3CHBrCH2CH3 on treatment with CH3CH2O(–).
You should view this animation from several aspects in order to see the all the changes taking place.
Ball&Stick Model Approximate Transition State Stop Motion (on/off) | Ball&Stick Model Approximate Transition State Stop Motion (on/off) |
This animation may be manipulated at any time by click-dragging the image.
'); generator.document.write('The E2 elimination of 2-bromo-2,3-dimethylbutane yields different product mixtures, depending on the size of the base. With methoxide the more highly substituted (Zaitsev Rule) double bond product, 2,3-dimethyl-2-butene, is produced in 80%, whereas the less substituted double bond in 2,3-dimethyl-1-butene accounts for 20%. With tert-butoxide the product ratio nearly reverses to 25% : 75%. The following models illustrate the influence of steric hindrance on this reaction.
In all cases an anti-transition state is assumed, with the base approaching the alkyl halide from below. The α and β carbon atoms are colored deep blue and are slightly distorted to reflect rehybridization. The β C-H and the C-Br bonds have been lengthened to 1.25 and 2.1 Angstroms respectively to indicate partial breaking, and the alkoxide oxygen β-H distance is set at 1.8 Angstroms with a thin green line representing the incipient bond. These transition state models are initially shown in the ball & stick form, but should be viewed in the space-filling mode to appreciate the steric hindrance effect.
2,3-Dimethyl-2-Butene Transition State | 2,3-Dimethyl-1-Butene Transition State | ||
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Methoxide | |||
Show Ball&Stick Model | Show Ball&Stick Model | ||
tert-Butoxide | |||
Show Ball&Stick Model | Show Ball&Stick Model |
Reactions which involve the formation of charged atoms and molecules are usually extremely endothermic in the gas phase, but may become spontaneous in certain solvents. If ions are formed from a neutral compound, as when NaCl is dissolved in water, the oppositely charged cations and anions naturally attract each other, so formation of a dispersed homogeneous solution might appear to be energetically unfavorable. To achieve charge separation of ions in solution, two solvent characteristics are particularly important. The first is the ability of solvent molecules to orient themselves between ions so as to attenuate the electrostatic force one ion exerts on the other. This characteristic is a function of the polarity of the solvent. Solvent polarity has been defined and measured in several different ways, one of the most common being the dielectric constant, ε. High dielectric constant solvents such as water (ε=80), dimethyl sulfoxide (ε=48) & N,N-dimethylformamide (ε=39), usually have polar functional groups, and often high dipole moments. When subject to the electric field of an ion, such polar molecules orient themselves to oppose the field, and in so doing they limit its reach. Because of electrostatic attraction between these polar groups, the boiling points of these solvents are generally higher than those of similarly sized nonpolar solvents, such as diethyl ether (ε=4.3) and hexane (ε=1.9).
Solvents that have relatively acidic hydrogen atoms (e.g. O-H & N-H) are called protic. Because their functional groups are made up of polar covalent bonds, protic solvents are often polar as well. A list of common protic and aprotic solvents is provided here. The dielectric constants provide a measure of solvent polarity.
Protic Solvents | Aprotic Solvents | |||||
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Compound | Boiling Pt. | Dielectric Const. | Compound | Boiling Pt. | Dielectric Const. | |
Water | 100 ºC | ε = 80 | DMSO | 189 ºC | ε = 46.7 | |
Formic Acid | 100º | 58.5 | DMF | 153º | 39 | |
Ethylene Glycol | 197º | 37.7 | Nitromethane | 101º | 37.3 | |
Methanol | 65º | 32.9 | Acetonitrile | 82º | 36.6 | |
2,2,2-Trifluoroethanol | 79º | 26.5 | Acetone | 56º | 20.7 | |
Ethanol | 78º | 24.6 | Pyridine | 115º | 12.4 | |
Ammonia | -33º | 22.4 | Methylene Chloride | 40º | 8.9 | |
Isopropanol | 82º | 19.9 | Ethyl Acetate | 77º | 6.0 | |
Acetic Acid | 118º | 6.2 | Diethyl Ether | 35º | 4.3 | |
Diethyl Amine | 55º | 3.6 | Benzene | 80º | 2.3 | |
Propanoic acid | 141º | 3.4 | Hexane | 69º | 1.9 |
The second factor important in the stabilization of ions, which also resists their intimate recombination, is called solvation. This refers to the ability of solvent molecules to stabilize ions by encasing them in a sheath of weakly bonded solvent molecules, thus somewhat dispersing the electrical charge. Anions are best solvated by hydrogen-bonding solvents; cations are generally solvated by binding to nucleophilic sites on a solvent molecule Two-dimensional diagrams illustrating the primary solvation shell about Na(+) and Cl(–) are shown here. The water dipoles are drawn as red arrows, and partial charges are noted. Additional water molecules are oriented in secondary and tertiary layers about the ions.
From this description of ion formation in solution, it should be clear that both enthalpy and entropy factors will be important to the outcome of an ionization process. Thus solvation stabilizes and insulates an ion, helping the enthalpic change, whereas the same solvation adds order and structure to the ionic species at the cost of lowering entropy. The outcome of these interactions is discussed below for two typical salts.
NaCl + H2O Na(+) + Cl(-) | ΔHº = +1.3 kcal/mole ΔSº = +10.3 cal/ ºK mole ΔGº = –1.3 kcal/mole | |||
CaF2 + H2O Ca(2+) + 2 F(-) | ΔHº = +1.5 kcal/mole ΔSº = –36.3 cal/ ºK mole ΔGº = +12.3 kcal/mole |
Although these two inorganic salts have similar standard enthalpies of solution in water, their standard entropies are quite different. One might expect this entropy change to be positive, since a single molecule in the solid state produces two or more ionic species, accompanied by an increase in system disorder. However this argument fails to consider the ordering of solvent molecules taking place in the solvation of these ions. Because of their greater charge density, small ions and highly charged ions, such as F– and Ca2+, require greater solvation than large or singly charged ions, such as Na+ or Cl–. The overall entropy change for solution of NaCl is positive, reflecting the increased disorder of ionization, but the entropy change for CaF2 solution is strongly negative thanks to the solvation shell structure required by the resulting ions. These different entropy changes are incorporated in the free energy of solution, which is exergonic for NaCl, but endergonic for CaF2. The result is dramatic. Sodium chloride is quite soluble in water at room temperature (36g per 100g water), but calcium fluoride is nearly insoluble (0.0016g per 100g water).
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