Empirical and Molecular Formulas

Combustion analysis is commonly used to determine the percent composition of carbon and hydrogen in a sample of a pure compound. Oxygen can not be determined by combustion analysis, and is usually estimated by difference. Other elements such as nitrogen, chlorine and sulfur can be measured directly in other ways.
An empirical formula is derived from the elemental composition of a compound. It represents the simplest whole number ratio of the different kinds of atoms that make up a molecule of a given compound. The molecular formula of a compound gives the actual number of the different atoms in a molecule. To convert an empirical formula into a molecular formula a molecular weight measurement is needed.
The elemental order in such formulas is: CHOZ, where Z = other elements. Do not try to subscript numbers. For question VI enter two or more letters or X for none.

I. A gaseous compound is found to be 74.9% C and 24.9% H. What is the empirical formula of this compound? ...
II. A liquid compound is found to be 52.1% C and 13.1% H. What is the empirical formula of this compound? ...
III. A liquid compound is found to be 48.7% C, 13.6% H and 37.8% N. What is the empirical formula of this compound? ...
IV. A liquid compound is found to be 29.8% C, 6.3% H and 44.0% Cl. What is the empirical formula of this compound? ...
V. A dark blue solid is found to be 73.3% C, 3.8% H and 10.7% N. Its molecular weight is roughly 260.
What is the molecular formula of this compound? ...
VI. Which of the following molecular formulas, if any, have the same empirical formula?
A. C6H4O2,     B. C6H12O6,     C. C12H8O4,     D. C3H8O6 ...

Consider the following molecular formulas.

     


This script written by William Reusch, Dept. of Chemistry, Michigan State University. Please send comments and corrections to whreusch@msu.edu.